3.223 \(\int \frac {x^{11} (c+d x^3+e x^6+f x^9)}{a+b x^3} \, dx\)

Optimal. Leaf size=208 \[ \frac {x^{12} \left (a^2 f-a b e+b^2 d\right )}{12 b^3}-\frac {a^3 \log \left (a+b x^3\right ) \left (a^3 (-f)+a^2 b e-a b^2 d+b^3 c\right )}{3 b^7}+\frac {a^2 x^3 \left (a^3 (-f)+a^2 b e-a b^2 d+b^3 c\right )}{3 b^6}-\frac {a x^6 \left (a^3 (-f)+a^2 b e-a b^2 d+b^3 c\right )}{6 b^5}+\frac {x^9 \left (a^3 (-f)+a^2 b e-a b^2 d+b^3 c\right )}{9 b^4}+\frac {x^{15} (b e-a f)}{15 b^2}+\frac {f x^{18}}{18 b} \]

[Out]

1/3*a^2*(-a^3*f+a^2*b*e-a*b^2*d+b^3*c)*x^3/b^6-1/6*a*(-a^3*f+a^2*b*e-a*b^2*d+b^3*c)*x^6/b^5+1/9*(-a^3*f+a^2*b*
e-a*b^2*d+b^3*c)*x^9/b^4+1/12*(a^2*f-a*b*e+b^2*d)*x^12/b^3+1/15*(-a*f+b*e)*x^15/b^2+1/18*f*x^18/b-1/3*a^3*(-a^
3*f+a^2*b*e-a*b^2*d+b^3*c)*ln(b*x^3+a)/b^7

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Rubi [A]  time = 0.32, antiderivative size = 208, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 30, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.067, Rules used = {1821, 1620} \[ \frac {x^9 \left (a^2 b e+a^3 (-f)-a b^2 d+b^3 c\right )}{9 b^4}-\frac {a x^6 \left (a^2 b e+a^3 (-f)-a b^2 d+b^3 c\right )}{6 b^5}+\frac {a^2 x^3 \left (a^2 b e+a^3 (-f)-a b^2 d+b^3 c\right )}{3 b^6}-\frac {a^3 \log \left (a+b x^3\right ) \left (a^2 b e+a^3 (-f)-a b^2 d+b^3 c\right )}{3 b^7}+\frac {x^{12} \left (a^2 f-a b e+b^2 d\right )}{12 b^3}+\frac {x^{15} (b e-a f)}{15 b^2}+\frac {f x^{18}}{18 b} \]

Antiderivative was successfully verified.

[In]

Int[(x^11*(c + d*x^3 + e*x^6 + f*x^9))/(a + b*x^3),x]

[Out]

(a^2*(b^3*c - a*b^2*d + a^2*b*e - a^3*f)*x^3)/(3*b^6) - (a*(b^3*c - a*b^2*d + a^2*b*e - a^3*f)*x^6)/(6*b^5) +
((b^3*c - a*b^2*d + a^2*b*e - a^3*f)*x^9)/(9*b^4) + ((b^2*d - a*b*e + a^2*f)*x^12)/(12*b^3) + ((b*e - a*f)*x^1
5)/(15*b^2) + (f*x^18)/(18*b) - (a^3*(b^3*c - a*b^2*d + a^2*b*e - a^3*f)*Log[a + b*x^3])/(3*b^7)

Rule 1620

Int[(Px_)*((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[Px*(a + b*x)
^m*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && PolyQ[Px, x] && (IntegersQ[m, n] || IGtQ[m, -2]) &&
GtQ[Expon[Px, x], 2]

Rule 1821

Int[(Pq_)*(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] -
1)*SubstFor[x^n, Pq, x]*(a + b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && PolyQ[Pq, x^n] && Intege
rQ[Simplify[(m + 1)/n]]

Rubi steps

\begin {align*} \int \frac {x^{11} \left (c+d x^3+e x^6+f x^9\right )}{a+b x^3} \, dx &=\frac {1}{3} \operatorname {Subst}\left (\int \frac {x^3 \left (c+d x+e x^2+f x^3\right )}{a+b x} \, dx,x,x^3\right )\\ &=\frac {1}{3} \operatorname {Subst}\left (\int \left (-\frac {a^2 \left (-b^3 c+a b^2 d-a^2 b e+a^3 f\right )}{b^6}+\frac {a \left (-b^3 c+a b^2 d-a^2 b e+a^3 f\right ) x}{b^5}+\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) x^2}{b^4}+\frac {\left (b^2 d-a b e+a^2 f\right ) x^3}{b^3}+\frac {(b e-a f) x^4}{b^2}+\frac {f x^5}{b}+\frac {a^3 \left (-b^3 c+a b^2 d-a^2 b e+a^3 f\right )}{b^6 (a+b x)}\right ) \, dx,x,x^3\right )\\ &=\frac {a^2 \left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) x^3}{3 b^6}-\frac {a \left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) x^6}{6 b^5}+\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) x^9}{9 b^4}+\frac {\left (b^2 d-a b e+a^2 f\right ) x^{12}}{12 b^3}+\frac {(b e-a f) x^{15}}{15 b^2}+\frac {f x^{18}}{18 b}-\frac {a^3 \left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \log \left (a+b x^3\right )}{3 b^7}\\ \end {align*}

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Mathematica [A]  time = 0.11, size = 187, normalized size = 0.90 \[ \frac {60 a^3 \log \left (a+b x^3\right ) \left (a^3 f-a^2 b e+a b^2 d-b^3 c\right )+b x^3 \left (-60 a^5 f+30 a^4 b \left (2 e+f x^3\right )-10 a^3 b^2 \left (6 d+3 e x^3+2 f x^6\right )+5 a^2 b^3 \left (12 c+6 d x^3+4 e x^6+3 f x^9\right )-a b^4 x^3 \left (30 c+20 d x^3+15 e x^6+12 f x^9\right )+b^5 x^6 \left (20 c+15 d x^3+12 e x^6+10 f x^9\right )\right )}{180 b^7} \]

Antiderivative was successfully verified.

[In]

Integrate[(x^11*(c + d*x^3 + e*x^6 + f*x^9))/(a + b*x^3),x]

[Out]

(b*x^3*(-60*a^5*f + 30*a^4*b*(2*e + f*x^3) - 10*a^3*b^2*(6*d + 3*e*x^3 + 2*f*x^6) + 5*a^2*b^3*(12*c + 6*d*x^3
+ 4*e*x^6 + 3*f*x^9) + b^5*x^6*(20*c + 15*d*x^3 + 12*e*x^6 + 10*f*x^9) - a*b^4*x^3*(30*c + 20*d*x^3 + 15*e*x^6
+ 12*f*x^9)) + 60*a^3*(-(b^3*c) + a*b^2*d - a^2*b*e + a^3*f)*Log[a + b*x^3])/(180*b^7)

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fricas [A]  time = 0.75, size = 210, normalized size = 1.01 \[ \frac {10 \, b^{6} f x^{18} + 12 \, {\left (b^{6} e - a b^{5} f\right )} x^{15} + 15 \, {\left (b^{6} d - a b^{5} e + a^{2} b^{4} f\right )} x^{12} + 20 \, {\left (b^{6} c - a b^{5} d + a^{2} b^{4} e - a^{3} b^{3} f\right )} x^{9} - 30 \, {\left (a b^{5} c - a^{2} b^{4} d + a^{3} b^{3} e - a^{4} b^{2} f\right )} x^{6} + 60 \, {\left (a^{2} b^{4} c - a^{3} b^{3} d + a^{4} b^{2} e - a^{5} b f\right )} x^{3} - 60 \, {\left (a^{3} b^{3} c - a^{4} b^{2} d + a^{5} b e - a^{6} f\right )} \log \left (b x^{3} + a\right )}{180 \, b^{7}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^11*(f*x^9+e*x^6+d*x^3+c)/(b*x^3+a),x, algorithm="fricas")

[Out]

1/180*(10*b^6*f*x^18 + 12*(b^6*e - a*b^5*f)*x^15 + 15*(b^6*d - a*b^5*e + a^2*b^4*f)*x^12 + 20*(b^6*c - a*b^5*d
+ a^2*b^4*e - a^3*b^3*f)*x^9 - 30*(a*b^5*c - a^2*b^4*d + a^3*b^3*e - a^4*b^2*f)*x^6 + 60*(a^2*b^4*c - a^3*b^3
*d + a^4*b^2*e - a^5*b*f)*x^3 - 60*(a^3*b^3*c - a^4*b^2*d + a^5*b*e - a^6*f)*log(b*x^3 + a))/b^7

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giac [A]  time = 0.17, size = 246, normalized size = 1.18 \[ \frac {10 \, b^{5} f x^{18} - 12 \, a b^{4} f x^{15} + 12 \, b^{5} x^{15} e + 15 \, b^{5} d x^{12} + 15 \, a^{2} b^{3} f x^{12} - 15 \, a b^{4} x^{12} e + 20 \, b^{5} c x^{9} - 20 \, a b^{4} d x^{9} - 20 \, a^{3} b^{2} f x^{9} + 20 \, a^{2} b^{3} x^{9} e - 30 \, a b^{4} c x^{6} + 30 \, a^{2} b^{3} d x^{6} + 30 \, a^{4} b f x^{6} - 30 \, a^{3} b^{2} x^{6} e + 60 \, a^{2} b^{3} c x^{3} - 60 \, a^{3} b^{2} d x^{3} - 60 \, a^{5} f x^{3} + 60 \, a^{4} b x^{3} e}{180 \, b^{6}} - \frac {{\left (a^{3} b^{3} c - a^{4} b^{2} d - a^{6} f + a^{5} b e\right )} \log \left ({\left | b x^{3} + a \right |}\right )}{3 \, b^{7}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^11*(f*x^9+e*x^6+d*x^3+c)/(b*x^3+a),x, algorithm="giac")

[Out]

1/180*(10*b^5*f*x^18 - 12*a*b^4*f*x^15 + 12*b^5*x^15*e + 15*b^5*d*x^12 + 15*a^2*b^3*f*x^12 - 15*a*b^4*x^12*e +
20*b^5*c*x^9 - 20*a*b^4*d*x^9 - 20*a^3*b^2*f*x^9 + 20*a^2*b^3*x^9*e - 30*a*b^4*c*x^6 + 30*a^2*b^3*d*x^6 + 30*
a^4*b*f*x^6 - 30*a^3*b^2*x^6*e + 60*a^2*b^3*c*x^3 - 60*a^3*b^2*d*x^3 - 60*a^5*f*x^3 + 60*a^4*b*x^3*e)/b^6 - 1/
3*(a^3*b^3*c - a^4*b^2*d - a^6*f + a^5*b*e)*log(abs(b*x^3 + a))/b^7

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maple [A]  time = 0.05, size = 266, normalized size = 1.28 \[ \frac {f \,x^{18}}{18 b}-\frac {a f \,x^{15}}{15 b^{2}}+\frac {e \,x^{15}}{15 b}+\frac {a^{2} f \,x^{12}}{12 b^{3}}-\frac {a e \,x^{12}}{12 b^{2}}+\frac {d \,x^{12}}{12 b}-\frac {a^{3} f \,x^{9}}{9 b^{4}}+\frac {a^{2} e \,x^{9}}{9 b^{3}}-\frac {a d \,x^{9}}{9 b^{2}}+\frac {c \,x^{9}}{9 b}+\frac {a^{4} f \,x^{6}}{6 b^{5}}-\frac {a^{3} e \,x^{6}}{6 b^{4}}+\frac {a^{2} d \,x^{6}}{6 b^{3}}-\frac {a c \,x^{6}}{6 b^{2}}-\frac {a^{5} f \,x^{3}}{3 b^{6}}+\frac {a^{4} e \,x^{3}}{3 b^{5}}-\frac {a^{3} d \,x^{3}}{3 b^{4}}+\frac {a^{2} c \,x^{3}}{3 b^{3}}+\frac {a^{6} f \ln \left (b \,x^{3}+a \right )}{3 b^{7}}-\frac {a^{5} e \ln \left (b \,x^{3}+a \right )}{3 b^{6}}+\frac {a^{4} d \ln \left (b \,x^{3}+a \right )}{3 b^{5}}-\frac {a^{3} c \ln \left (b \,x^{3}+a \right )}{3 b^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^11*(f*x^9+e*x^6+d*x^3+c)/(b*x^3+a),x)

[Out]

1/18*f*x^18/b-1/15/b^2*x^15*a*f+1/15/b*x^15*e+1/12/b^3*x^12*a^2*f-1/12/b^2*x^12*a*e+1/12/b*x^12*d-1/9/b^4*x^9*
a^3*f+1/9/b^3*x^9*a^2*e-1/9/b^2*x^9*a*d+1/9/b*x^9*c+1/6/b^5*x^6*a^4*f-1/6/b^4*x^6*a^3*e+1/6/b^3*x^6*a^2*d-1/6/
b^2*x^6*a*c-1/3/b^6*x^3*a^5*f+1/3/b^5*x^3*a^4*e-1/3/b^4*x^3*a^3*d+1/3/b^3*x^3*a^2*c+1/3*a^6/b^7*ln(b*x^3+a)*f-
1/3*a^5/b^6*ln(b*x^3+a)*e+1/3*a^4/b^5*ln(b*x^3+a)*d-1/3*a^3/b^4*ln(b*x^3+a)*c

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maxima [A]  time = 1.37, size = 209, normalized size = 1.00 \[ \frac {10 \, b^{5} f x^{18} + 12 \, {\left (b^{5} e - a b^{4} f\right )} x^{15} + 15 \, {\left (b^{5} d - a b^{4} e + a^{2} b^{3} f\right )} x^{12} + 20 \, {\left (b^{5} c - a b^{4} d + a^{2} b^{3} e - a^{3} b^{2} f\right )} x^{9} - 30 \, {\left (a b^{4} c - a^{2} b^{3} d + a^{3} b^{2} e - a^{4} b f\right )} x^{6} + 60 \, {\left (a^{2} b^{3} c - a^{3} b^{2} d + a^{4} b e - a^{5} f\right )} x^{3}}{180 \, b^{6}} - \frac {{\left (a^{3} b^{3} c - a^{4} b^{2} d + a^{5} b e - a^{6} f\right )} \log \left (b x^{3} + a\right )}{3 \, b^{7}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^11*(f*x^9+e*x^6+d*x^3+c)/(b*x^3+a),x, algorithm="maxima")

[Out]

1/180*(10*b^5*f*x^18 + 12*(b^5*e - a*b^4*f)*x^15 + 15*(b^5*d - a*b^4*e + a^2*b^3*f)*x^12 + 20*(b^5*c - a*b^4*d
+ a^2*b^3*e - a^3*b^2*f)*x^9 - 30*(a*b^4*c - a^2*b^3*d + a^3*b^2*e - a^4*b*f)*x^6 + 60*(a^2*b^3*c - a^3*b^2*d
+ a^4*b*e - a^5*f)*x^3)/b^6 - 1/3*(a^3*b^3*c - a^4*b^2*d + a^5*b*e - a^6*f)*log(b*x^3 + a)/b^7

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mupad [B]  time = 4.92, size = 237, normalized size = 1.14 \[ x^{15}\,\left (\frac {e}{15\,b}-\frac {a\,f}{15\,b^2}\right )+x^{12}\,\left (\frac {d}{12\,b}-\frac {a\,\left (\frac {e}{b}-\frac {a\,f}{b^2}\right )}{12\,b}\right )+x^9\,\left (\frac {c}{9\,b}-\frac {a\,\left (\frac {d}{b}-\frac {a\,\left (\frac {e}{b}-\frac {a\,f}{b^2}\right )}{b}\right )}{9\,b}\right )+\frac {\ln \left (b\,x^3+a\right )\,\left (f\,a^6-e\,a^5\,b+d\,a^4\,b^2-c\,a^3\,b^3\right )}{3\,b^7}+\frac {f\,x^{18}}{18\,b}+\frac {a^2\,x^3\,\left (\frac {c}{b}-\frac {a\,\left (\frac {d}{b}-\frac {a\,\left (\frac {e}{b}-\frac {a\,f}{b^2}\right )}{b}\right )}{b}\right )}{3\,b^2}-\frac {a\,x^6\,\left (\frac {c}{b}-\frac {a\,\left (\frac {d}{b}-\frac {a\,\left (\frac {e}{b}-\frac {a\,f}{b^2}\right )}{b}\right )}{b}\right )}{6\,b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^11*(c + d*x^3 + e*x^6 + f*x^9))/(a + b*x^3),x)

[Out]

x^15*(e/(15*b) - (a*f)/(15*b^2)) + x^12*(d/(12*b) - (a*(e/b - (a*f)/b^2))/(12*b)) + x^9*(c/(9*b) - (a*(d/b - (
a*(e/b - (a*f)/b^2))/b))/(9*b)) + (log(a + b*x^3)*(a^6*f - a^3*b^3*c + a^4*b^2*d - a^5*b*e))/(3*b^7) + (f*x^18
)/(18*b) + (a^2*x^3*(c/b - (a*(d/b - (a*(e/b - (a*f)/b^2))/b))/b))/(3*b^2) - (a*x^6*(c/b - (a*(d/b - (a*(e/b -
(a*f)/b^2))/b))/b))/(6*b)

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sympy [A]  time = 1.32, size = 216, normalized size = 1.04 \[ \frac {a^{3} \left (a^{3} f - a^{2} b e + a b^{2} d - b^{3} c\right ) \log {\left (a + b x^{3} \right )}}{3 b^{7}} + x^{15} \left (- \frac {a f}{15 b^{2}} + \frac {e}{15 b}\right ) + x^{12} \left (\frac {a^{2} f}{12 b^{3}} - \frac {a e}{12 b^{2}} + \frac {d}{12 b}\right ) + x^{9} \left (- \frac {a^{3} f}{9 b^{4}} + \frac {a^{2} e}{9 b^{3}} - \frac {a d}{9 b^{2}} + \frac {c}{9 b}\right ) + x^{6} \left (\frac {a^{4} f}{6 b^{5}} - \frac {a^{3} e}{6 b^{4}} + \frac {a^{2} d}{6 b^{3}} - \frac {a c}{6 b^{2}}\right ) + x^{3} \left (- \frac {a^{5} f}{3 b^{6}} + \frac {a^{4} e}{3 b^{5}} - \frac {a^{3} d}{3 b^{4}} + \frac {a^{2} c}{3 b^{3}}\right ) + \frac {f x^{18}}{18 b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**11*(f*x**9+e*x**6+d*x**3+c)/(b*x**3+a),x)

[Out]

a**3*(a**3*f - a**2*b*e + a*b**2*d - b**3*c)*log(a + b*x**3)/(3*b**7) + x**15*(-a*f/(15*b**2) + e/(15*b)) + x*
*12*(a**2*f/(12*b**3) - a*e/(12*b**2) + d/(12*b)) + x**9*(-a**3*f/(9*b**4) + a**2*e/(9*b**3) - a*d/(9*b**2) +
c/(9*b)) + x**6*(a**4*f/(6*b**5) - a**3*e/(6*b**4) + a**2*d/(6*b**3) - a*c/(6*b**2)) + x**3*(-a**5*f/(3*b**6)
+ a**4*e/(3*b**5) - a**3*d/(3*b**4) + a**2*c/(3*b**3)) + f*x**18/(18*b)

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